Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises - Page 389: 88

Answer

$\approx 1.198970$

Work Step by Step

RECALL: The change-of-base formula for logarithms: $\log_b{x} = \dfrac{\log_a{x}}{\log_a{b}}$ Use the formula above and use base 10 to obtain: $\log_{100}{250} = \dfrac{\log{250}}{\log{100}}$ Use a scientific calculator and round-off the answer to six decimal places to obtain: $\approx 1.198970$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.