Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises - Page 390: 89

Answer

$\log_4{258} \gt \log_5{620}$

Work Step by Step

RECALL: The change-of-base formula for logarithms: $\log_b{x} = \dfrac{\log_a{x}}{\log_a{b}}$ Use the formula above and use base 10 to evaluate each of the given logarithms: $\log_{4}{258} = \dfrac{\log{258}}{\log{4}}\approx 4.005614$ $\log_5{620} = \dfrac{\log{620}}{\log{5}} \approx 3.995009$ Thus, $\log_4{258} \gt \log_5{620}$.
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