Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises - Page 389: 27

Answer

$x = \log 74$

Work Step by Step

$Write$ $the$ $equation$ $in$ $logarithmic$ $form:$ $10^x = 74$ Exponential form to logarithmic form: $b^c = a \rightarrow \log_b a = c$ Plug in 10 for b, x for c, and 74 for a $$10^x = 74 \rightarrow \log_{10} 74 = x$$ $$\log 74 = x$$ $$x = \log 74$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.