Answer
$$\log (x^3y^4)$$
Work Step by Step
$Combine$ $into$ $a$ $single$ $logarithm:$
$\log x + \log (x^2y) + 3\log y$
Use the Third Law of Logarithms for $3\log y$
$3\log y = \log y^3$
$\log x + \log (x^2y) + \log y^3$
Use the First Law of Logarithms
$\log x + \log (x^2y) + \log y^3$ = $\log (x\times x^2y\times y^3)$
$$\log (x^3y^4)$$