Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises - Page 389: 51

Answer

$\log 96$

Work Step by Step

$Combine$ $into$ $a$ $single$ $logarithm:$ $\log 6 + 4\log 2$ Use the Third Law of Logarithms for $4\log 2$ $4\log 2 = \log 2^4 = \log 16$ $\log 6 + \log 16$ Use the First Law of Logarithms $\log 6 + \log 16 = \log (6\times16) = \log 96$
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