## Precalculus: Mathematics for Calculus, 7th Edition

$x=\dfrac{3}{2}+\dfrac{1}{2e}\approx1.68$
$\ln(2x-3)+1=0$ Take $1$ to the right side: $\ln(2x-3)=-1$ Rewrite this equation in exponential form: $2x-3=e^{-1}$ Solve for $x$: $2x-3=\dfrac{1}{e}$ $2x=3+\dfrac{1}{e}$ $x=\dfrac{3}{2}+\dfrac{1}{2e}\approx1.68$