Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises: 42



Work Step by Step

$Evaluate$ $the$ $expression$ $without$ $using$ $a$ $calculator:$ $\log_250 - \log_5 2$ Use the Second Law of Logarithms: $\log A - \log B = \log (\frac{A}{B})$ $$\log_5 250 - \log_5 2 = \log_5 (\frac{250}{2})$$ $$\log_5 125$$ Rewrite 125 as $5^3$ $$\log_5 5^3$$ Use the Third Property of Logarithms: $\log_a a^x = x$ $$\log_5 5^3 = 3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.