Answer
$x^2(x+2i)(x-2i)$ Roots are 0, 2i and -2i
Work Step by Step
We see a factor of $x^2$ so lets factor that out. We get $x^2(x^2+4)$ This is equal to $x^2(x+2i)(x-2i)$ so the roots are 0, 2i and -2i.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.5 - Complex Zeros and the Fundamental Theorem of Algebra - 3.5 Exercises - Page 293: 7
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