Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.6 - The Binomial Theorem - 12.6 Exercises - Page 886: 33

Answer

$48,620x^{18}$

Work Step by Step

$(a+b)^{n}=\left(\begin{array}{l} n\\ 0 \end{array}\right)a^{n}+\left(\begin{array}{l} n\\ 1 \end{array}\right)a^{n-1}b+\left(\begin{array}{l} n\\ 2 \end{array}\right)a^{n-2}b^{2}+\cdots+\left(\begin{array}{l} n\\ n \end{array}\right)b^{n}$ $\displaystyle \left(\begin{array}{l} n\\ r \end{array}\right)=\frac{n!}{r!(n-r)!},$ $n!=n(n-1)\cdot...\cdot 2\cdot 1,$ $ 0!=1$ -------- $...$In all the terms, exponents of a and b add to n... In $(a+b)^{18}$ the middle term in the expansion is where exponents of a and b are 9. So for $(x^{2}+1)^{18}$ this term is $\left(\begin{array}{l} 18\\ 9 \end{array}\right)(x^{2})^{9}1^{9}=$ $=\displaystyle \frac{18\cdot 17\cdot 16\cdot 15\cdot 14\cdot 13\cdot 12\cdot 11\cdot 10}{1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7\cdot 8\cdot 9}\cdot x^{18}$ $=48,620x^{18}$
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