Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.6 - The Binomial Theorem - 12.6 Exercises - Page 886: 27

Answer

$1+\frac{6}{x}+\frac{15}{x^{2}}+\frac{20}{x^{3}}+\frac{15}{x^{4}}+\frac{6}{x^{5}}+\frac{1}{x^{6}}$

Work Step by Step

$(1+\frac{1}{x})^{6}=\,^6C_0\times1^{6}\times(\frac{1}{x})^{0}+\,^6C_1\times1^{5}\times(\frac{1}{x})^{1}+\,^6C_2\times1^{4}\times(\frac{1}{x})^{2}+\,^6C_3\times1^{3}\times(\frac{1}{x})^{3}+\,^6C_4\times1^{2}\times(\frac{1}{x})^{4}+\,^6C_5\times1^{1}\times(\frac{1}{x})^{5}+\,^6C_6\times1^{0}\times(\frac{1}{x})^{6}$ $=(1\times1\times1)+(6\times1\times\frac{1}{x})+(15\times1\times\frac{1}{x^{2}})+(20\times1\times\frac{1}{x^{3}})+(15\times1\times\frac{1}{x^{4}})+(6\times1\times\frac{1}{x^{5}})+(1\times1\times\frac{1}{x^{6}})$ $=1+\frac{6}{x}+\frac{15}{x^{2}}+\frac{20}{x^{3}}+\frac{15}{x^{4}}+\frac{6}{x^{5}}+\frac{1}{x^{6}}$
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