Answer
$252$
Work Step by Step
$ \binom {10}{5} =\dfrac {10!}{5!\times \left( 10-5\right) !}=\dfrac {5!\times 6\times 7\times 8\times 9\times 10}{5!\times 5!}=\dfrac {6\times 7\times 8\times 9\times 10}{1\times 2\times 3\times 4\times 5}=252$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Section 12.6 - The Binomial Theorem - 12.6 Exercises - Page 886: 20
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