Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 754: 9

{$3,4$} and {$-3,4$}

Given: $x^2-2y=1$ and $x^2+5y=29$ This implies that $x^2+5y-x^2+2y=29-1$ Then, we have $7y=28$ This gives: $y=4$ At $y= 4$, we have $x^2-2(4)=1 \implies x^2-8=1$ or, $x=\pm \sqrt 9 =\pm 3$ Thus, the solutions set are: {$3,4$} and {$-3,4$}