Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 754: 5

{$2,-2$} and {$-2,2$}

Given: $x^2+y^2=8$ and $x+y=0x$ This implies that $x=-y$ Then, we have $x^2+x^2=85$ or, $2x^2 =8$ This gives: $x=\pm \sqrt 4=\pm 2$ a) At $x= 2$, we have $y=-x=-2$ b) At $x=- 2$, we have $y=-x=-(-2)=2$ Thus, the solutions set are: {$2,-2$} and {$-2,2$}