Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 754: 22

$(2, 0)$ $(-2, 0)$

Given the system of equations: 1. $y = 4 - x^2$ 2. $y = x^2 - 4$ It asks to find all solutions. Substitute $y = 4-x^2$ $4 - x^2 = x^2 - 4$ $2x^2 = 8$ $x^2 = 4$ $x = 2, -2$ Substitute the values into the equation $y = 4 - 2^2$ $y = 0$ $y = 4 - (-2)^2$ $y = 0$ All solutions: $(2, 0)$ $(-2, 0)$