Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 754: 3

Answer

$(-3,9),(4,16)$

Work Step by Step

The substitution method involves taking part of another equation and plugging it into another in the system. In this system we will plug in $x^2$ for $y$ in $y=x+12$ (because $y=x^2$ according to the other equation). $x^2=x+12$ Subtract $x$ and $12$ to the other side. $x^2-x-12=0$ What factors of $-12$ will add up to $-1$, the coefficient of the middle term? $(x-4)(x+3)$ $x=-3,4$ Plug each of these into the equations $y=(-3)^2$ $y=9$ $y=-3+12$ $y=9$ $y=(4)^2$ $y=16$ $y=4+12$ $y=16$
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