Answer
$(4,0)$
Work Step by Step
Given the system of equations:
1. $y + x^2 = 4x$
2. $y + 4x = 16$
It asks to find all solutions.
Substitute $y = 16 - 4x$
$16 - 4x + x^2 = 4x$
$x^2 - 8x + 16 = 0$
$(x-4)^2 =0$
$x = 4$
Substitute the values into the equation
$y + 4(4) = 16$
$y = 0$
All solutions:
$(4,0)$
