Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 754: 30

Answer

$(2, 1)$ $(-2, 1)$

Work Step by Step

Given the system of equations: 1. $x^4 + y^3 = 17$ 2. $3x^4 + 5y^3 = 53$ It asks to find all solutions. Triple equation one, subtract the result from equation 2 $3x^4 + 5y^3 = 53$ - ($3x^4 + 3y^3 = 51$) $2y^3 = 2$ $y^3 = 1$ $y = 1$ Substitute the values into the equation $x^4 + 1^3 = 17$ $x^4= 16$ $x = -2, 2$ All solutions: $(2, 1)$ $(-2, 1)$
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