Answer
$\frac{19}{2}$ or $9.5$
Work Step by Step
Step 1. See graph, sketch the triangle with the given vertices.
Step 2. Recall the determinant formula for the area of a triangle:
$\begin{array}( \\A=\pm\frac{1}{2} \\ \\ \end{array}
\begin{vmatrix}1 &0&1\\3&5&1\\-2&2&1 \end{vmatrix}$
Step 3. Evaluate the determinant (row1 expansion for this case)
$A=\frac{1}{2}|(1)(5\times1-1\times2)+(1)(3\times2+5\times2)|=\frac{19}{2}=9.5$
