Answer
$(0.6, -0.4)$
Work Step by Step
Step 1. Based on the Cramer’s Rule, with the given equations, we can define the following determinants:
$\begin{array}( \\|D|= \\ \\ \end{array}
\begin{vmatrix} 1 &-6\\3 &2 \end{vmatrix},
\begin{array}( \\|D_x|= \\ \\ \end{array}
\begin{vmatrix} 3 &-6\\1 &2 \end{vmatrix},
\begin{array}( \\|D_y|= \\ \\ \end{array}
\begin{vmatrix} 1 &3\\3 &1 \end{vmatrix}$
Step 2. Evaluate the above determinants:
$|D|=1\times2-(-6\times3)=20$,
$|D_x|=3\times2-(-6\times1)=12$,
$|D_y|=1\times1-(3\times3)=-8$
Step 3. Find the solutions as:
$x=\frac{|D_x|}{|D|}=\frac{3}{5}=0.6$,
$y=\frac{|D_y|}{|D|}=-\frac{2}{5}=-0.4$
