Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.6 - Determinants and Cramer's Rule - 10.6 Exercises - Page 743: 44

Answer

$(-2, 6)$

Work Step by Step

Step 1. Based on the Cramer’s Rule, with the given equations, we can define the following determinants: $\begin{array}( \\|D|= \\ \\ \end{array} \begin{vmatrix} 1/2 &1/3\\1/4 &-1/6 \end{vmatrix}, \begin{array}( \\|D_x|= \\ \\ \end{array} \begin{vmatrix} 1 &1/3\\-3/2 &-1/6 \end{vmatrix}, \begin{array}( \\|D_y|= \\ \\ \end{array} \begin{vmatrix} 1/2 &1\\1/4 &-3/2 \end{vmatrix}$ Step 2. Evaluate the above determinants: $|D|=-\frac{1}{12}-\frac{1}{12}=-\frac{1}{6}$, $|D_x|=-\frac{1}{6}+\frac{1}{2}=\frac{1}{3}$, $|D_y|=-\frac{3}{4}-\frac{1}{4}=-1$ Step 3. Find the solutions as: $x=\frac{|D_x|}{|D|}=-2$, $y=\frac{|D_y|}{|D|}=6$
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