Answer
0, No.
Work Step by Step
Evaluate the determinant with cofactors:
$\begin{array}( \\|A|= \\ \\ \end{array}
\begin{vmatrix} 1 & 3 &7\\2 &0 &8\\0 &2 &2 \end{vmatrix} \begin{array}( \\= \\ \\\end{array}
\begin{vmatrix} 0 &8\\2 &2 \end{vmatrix} \begin{array}( \\-3 \\ \\\end{array}
\begin{vmatrix} 2 &8\\0&2 \end{vmatrix} \begin{array}( \\+7 \\ \\\end{array}
\begin{vmatrix} 2 &0\\0 &2 \end{vmatrix}$
$|A|=(-16)-3(4)+7(4)=0$
As $|A|=0$, the matrix does not have an inverse.
