Answer
2, Yes.
Work Step by Step
Evaluate the determinant with cofactors:
$\begin{array}( \\|A|= \\ \\ \end{array}
\begin{vmatrix} 0 & -1 &0\\2 &6 &4\\1 &0 &3 \end{vmatrix} \begin{array}( \\= \\ \\\end{array}
\begin{vmatrix} 2 &4\\1 &3 \end{vmatrix} $
$|A|=6-4=2$
As $|A|\ne0$, the matrix should have an inverse.