Answer
$0$, No
Work Step by Step
Evaluate the determinant with cofactors:
$\begin{array}( \\|A|= \\ \\ \end{array}
\begin{vmatrix} 1 & 2 &5\\-2 &-3 &2\\3 &5 &3 \end{vmatrix} \begin{array}( \\= \\ \\\end{array}
\begin{vmatrix} -3 &2\\5 &3 \end{vmatrix} \begin{array}( \\-2 \\ \\\end{array}
\begin{vmatrix} -2 &2\\3&3 \end{vmatrix} \begin{array}( \\+5 \\ \\\end{array}
\begin{vmatrix} -2 &-3\\3 &5 \end{vmatrix}$
$|A|=(-9-10)-2(-6-6)+5(-10+9)=0$
As $|A|=0$, the matrix does not have an inverse.
