Answer
$(x+1)^2+(y-1)^2=9$
Work Step by Step
RECALL:
The standard form of the equation of a circle whose center is at (h, k) and has a radius $r$ is:
$(x-h)^2+(y-k)^2=r^2$
The given circle has its center at (-1, 1) and has $r=3$.
Thus, its equation is:
$[x-(-1)]^2+(y-1)^2=3^2
\\(x+1)^2+(y-1)^2=9$