Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 104: 98

Answer

$(x+1)^2+(y-1)^2=9$

Work Step by Step

RECALL: The standard form of the equation of a circle whose center is at (h, k) and has a radius $r$ is: $(x-h)^2+(y-k)^2=r^2$ The given circle has its center at (-1, 1) and has $r=3$. Thus, its equation is: $[x-(-1)]^2+(y-1)^2=3^2 \\(x+1)^2+(y-1)^2=9$
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