Answer
$(x-5)^2+(y-5)^2=25$
Work Step by Step
RECALL:
The standard form of the equation of a circle whose center is at (h, k) and radius $r$ is:
$(x-h)^2+(y-k)^2=r^2$
The circle is in the first quadrant, with a radius of 5, and is tangent to both x and y axes.
This means that the center is 5 units to the right of the y-axis (x=5) and 5 units above the x-axis (y=5).
Thus, the center is at (5, 5).
Therefore, with a radius of 5 and center at (5, 5), the circle’s equation is:
$(x-5)^2+(y-5)^2=5^2
\\(x-5)^2+(y-5)^2=25$
