Answer
The given circle has:
center at (-1, 0)
radius = 3 units
Refer to the attached image for the graph
Work Step by Step
RECALL:
The standard equation of a circle whose center is at (h, k) and radius $r$ is:
$(x-h)^2+(y-k)^2=r^2$
The given equation is similar to the standard form given above.
Thus, the given equation represents a circle with center at (-1, 0) and
$r^2=9
\\r=\sqrt9
\\r=3$
Therefore, the given circle has:
center at (-1, 0)
radius = 3 units
Plot the points $(-4, 0), (2, 0), (-1, 3), \text{ and } (-1, -3)$ then connect them using a curve to form a circle.
Or, use a graphing calculator to have the graph attached in the answer part above.