Answer
The given circle has:
center at (-1, -2)
radius = 6 units
Refer to the attached image for the graph.
Work Step by Step
RECALL:
The standard equation of a circle whose center is at (h, k) and radius r is:
$(x-h)^2+(y-k)^2=r^2$
The given equation is similar to the standard form given above.
Thus, the given equation represents a circle with center at (-1, -2) and
$r^2=36
\\r=\sqrt{36}
\\r=6$
Therefore, the given circle has:
center at (-1, -2)
radius = 6 units
Plot the points (-7, 2),(5, -2),(-1, 4), and (-1, -8) then connect them using a curve to form a circle.
Or, use a graphing calculator to have the graph attached in the answer part above.
