Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 104: 97

$(x+2)^2+(y-2)^2=4$

RECALL: The standard form of the equation of a circle whose center is at (h, k) and has a radius $r$ is: $(x-h)^2+(y-k)^2=r^2$ The given circle has its center at (-2, 2) and has $r=2$. Thus, its equation is: $\\(x-(-2))^2+(y-2)^2=2^2$ $\\(x+2)^2+(y-2)^2=4$