Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 102: 35

Answer

The point $A$ is closer to the origin

Work Step by Step

$A(6,7);$ $B(-5,8)$ The distance between two points is given by the formula $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ Find the distance between point $A$ and the origin. For these two points, $x_{1}=6$, $y_{1}=7$, $x_{2}=0$ and $y_{2}=0$. Substitute the known values into the formula: $d_{AO}=\sqrt{(0-6)^{2}+(0-7)^{2}}=\sqrt{(-6)^{2}+(-7)^{2}}=...$ $...=\sqrt{36+49}=\sqrt{85}\approx9.2195$ Find the distance between point B and the origin. For these two points, $x_{1}=-5$, $y_{1}=8$, $x_{2}=0$ and $y_{2}=0$. Substitute the known values into the formula: $d_{BO}=\sqrt{(0+5)^{2}+(0-8)^{2}}=\sqrt{5^{2}+(-8)^{2}}=...$ $...=\sqrt{25+64}=\sqrt{89}\approx9.434$ Since $d_{AO}\lt d_{BO}$, the point $A$ is closer to the origin
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.