Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 102: 34

Answer

Point S is located at (0,-6) Area of Square PQRS is 50

Work Step by Step

Point S is located at (0,-6) because at (0,-6), all of the sides will have the same distance from one point to the other end point which results in a square area of square = $side^2$ distance of one side = $D =\sqrt (x_{2}-x_{1})^2 + (y_{2}-y_{1})^2$ $D =\sqrt (5-0)^2 + (1-6)^2$ $D =\sqrt (5)^2 + (-5)^2$ $D =\sqrt (25 + 25)$ $D =\sqrt (50)$ therefore the distance of one side = $\sqrt (50)$ area of square = $side^2$ area of square = $\sqrt (50)^2$ area of square = $50$
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