Answer
Area of rectangle ABCD is 24
Work Step by Step
The area of a rectangle is area = base times height $(b\times h)$ .
In rectangle ABCD segment AB is equal to CD therefore using the distance formula $D=\sqrt (x-x)^2 + (y-y)^2$ we find the distance from A to B for the side.
$D= \sqrt (1-5)^2 + (3-3)^2$
$D= \sqrt (-4)^2 + (0)^2$
$D= \sqrt (16+0)$
$D= \sqrt 16$
$D= 4$
for the other side we use the distance formula again to find the measure of A to C since AC is the same distance as BD
$D= \sqrt (1-1)^2 + (3+3)^2$
$D= \sqrt (0)^2 + (6)^2$
$D= \sqrt (0) + (36)$
$D= \sqrt 36$
$D= 6$
Therefore the area is $6\times 4$ which is 24
