Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 102: 24

Answer

distance between the two given points = $2\sqrt{10}$ units midpoint of the segment joining the two given points: $(1, -2)$

Work Step by Step

RECALL: (i) The distance, d, between the points (a, b) and (c, d) can be found using the distance formula: $\\d=\sqrt{(a-c)^2+(b-d)^2}$ (ii) The midpoint of the points (a, b) and (c, d) can be found using the midpoint formula: midpoint = $\left(\frac{a+c}{2},\frac{b+d}{2}\right)$ The two points are (-2, -3) and (4, -1). Use the formulas above to have: (a) distance between the two points: $\\=\sqrt{(-2-4)^2+[(-3-(-1)]^2} \\=\sqrt{(-6)^2+(-2)^2} \\=\sqrt{36+4} \\=\sqrt{40} \\=\sqrt{4(10)} \\=2\sqrt{10}$ (b) midpoint of the segment that joins them: $\\=\left(\frac{-2+4}{2}, \frac{-3+(-1)}{2}\right) \\=\left(\frac{2}{2}, \frac{-4}{2}\right) \\=(1, -2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.