Answer
This equation has two distinct real solutions.
Work Step by Step
$x^{2}-6x+1=0$
The formula for the discriminant is $D=b^{2}-4ac$. For this equation, $a=1$, $b=-6$ and $c=1$
Substitute the known values in the formula:
$D=(-6)^{2}-4(1)(1)=36-4=32$
Since $D\gt0$, this equation has two distinct real solutions.
