Answer
$x=4$
Work Step by Step
$\sqrt{2x-1}=\sqrt{3x-5}$
Let's square both sides of the equation:
$(\sqrt{2x-1})^{2}=(\sqrt{3x-5})^{2}$
$2x-1=3x-5$
Solve for $x$:
$2x-3x=-5+1$
$-x=-4$
$x=4$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 57: 95
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