Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 57: 93

Answer

$x=7$

Work Step by Step

$5=\sqrt{4x-3}$ Let's square both sides of the equation: $5^{2}=(\sqrt{4x-3})^{2}$ $25=4x-3$ Solve for $x$: $4x=28$ $x=\dfrac{28}{4}$ $x=7$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.