Answer
$x_1 = 1, x_2 = -6$
Work Step by Step
$Find$ $all$ $real$ $solutions$ $of$ $the$ $quadratic$ $equation:$
$x^2+5x-6$
Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$
$1x^2+5x-6$
$a = 1, b = 5, c = -6$
$x = \frac{-(5) \pm \sqrt {(5)^2- 4(1 \times -6)}}{2(1)}$
$x = \frac{-5 \pm \sqrt {25 + 24}}{2}$
$x = \frac{-5 \pm \sqrt {49}}{2}$
$x_1 = \frac{-5 + 7}{2}, x_2 = \frac{-5-7}{2}$
$x_1 = \frac{2}{2}, x_2 = \frac{-12}{2}$
$x_1 = 1, x_2 = -6$
