Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 57: 113

The solutions are $x=-\dfrac{4}{3}$ and $x=-2$

$|3x+5|=1$ By the definition of absolute value, solving this equation is equivalent to solve two separate equation, which are: $3x+5=1$ and $3x+5=-1$ Solve both equations for $x$: $3x+5=1$ $3x=1-5$ $3x=-4$ $x=-\dfrac{4}{3}$ $3x+5=-1$ $3x=-1-5$ $3x=-6$ $x=\dfrac{-6}{3}$ $x=-2$ The solutions are $x=-\dfrac{4}{3}$ and $x=-2$