Answer
$x_1 = 30, x_2 = -20$
Work Step by Step
Given:
$x^2+10x-600$
Use the Quadratic Equation Formula: $x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}$
$1x^2+10x-600$
$a = 1, b = 10, c = -600$
$x = \frac{-(10) \pm \sqrt {(10)^2- 4(1 \times -600)}}{2(1)}$
$x = \frac{-10 \pm \sqrt {100+ 2400}}{2}$
$x = \frac{-10 \pm \sqrt {2500}}{2}$
$x_1 = \frac{-10+50}{2}, x_2 = \frac{-10-50}{2}$
$x_1 = \frac{40}{2}, x_2 = \frac{-60}{2}$
$x_1 = 20, x_2 = -30$
