Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 55


The real solutions to the equation $(2x-5)^{2}=81$ are $x=-2$ and $x=7$

Work Step by Step

1. $(2x-5)^{2}=81$ 2. Take the square root of each side: $\sqrt(2x-5)^{2}=\sqrt81$:$2x-5=±9$ 3. Add 5 to each side: $2x=±9+5$ 4. Divide each side by 2: $x=\frac{±9+5}{2}$ 5. Solve: $x=\frac{14}{2}=7$ and $x=\frac{-4}{2}=-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.