Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 36


$x=\dfrac{a-2b+6c-6}{6}$ or $x=\dfrac{a}{6}-\dfrac{b}{3}+c-1$

Work Step by Step

$a-2[b-3(c-x)]=6;$ for $x$ Eliminate the grouping symbols by perfoming the indicated operations: $a-2[b-3c+3x]=6$ $a-2b+6c-6x=6$ Solve for $x$: $a-2b+6c=6+6x$ $6+6x=a-2b+6c$ $6x=a-2b+6c-6$ $x=\dfrac{a-2b+6c-6}{6}$ or $x=\dfrac{a}{6}-\dfrac{b}{3}+c-1$
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