Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 39


$r = \sqrt {\frac{3V}{\pi h}}$

Work Step by Step

$Solve$ $the$ $equation$ $for$ $the$ $indicated$ $variable:$ $V = \frac{1}{3}\pi r^2h;$ $for$ $r$ Solve for $r$ Multiply both sides by 3 $3\times V = 3(\frac{1}{3}\pi r^2h)$ $3V = \pi r^2h$ Divide Both sides by $\pi h$ $\frac{3V}{\pi h} = \frac{\pi r^2h}{\pi h}$ $\frac{3V}{\pi h} = r^2$ Square root both sides $\sqrt {r^2} = \sqrt {\frac{3V}{\pi h}}$ $r = \sqrt {\frac{3V}{\pi h}}$
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