Precalculus: Mathematics for Calculus, 7th Edition

$x=30$
$x-\dfrac{1}{3}x-\dfrac{1}{2}x-5=0$ Let's multiply the whole equation by the least common multiple of $3$ and $2$, that are the denominators present in the equation. We will do this to avoid working with fractions $LCM(3,2)=6$ $(x-\dfrac{1}{3}x-\dfrac{1}{2}x-5=0)(6)$ $6x-6(\dfrac{1}{3}x)-6(\dfrac{1}{2}x)-30=0$ $6x-2x-3x-30=0$ Simplify like terms and solve for $x$: $6x-2x-3x=30$ $x=30$