## Precalculus: Mathematics for Calculus, 7th Edition

$x=\dfrac{13}{6}$
$\dfrac{2x-1}{x+2}=\dfrac{4}{5}$ We can apply cross-multiplication to solve this equation. $5(2x-1)=4(x+2)$ Evaluate the products: $10x-5=4x+8$ Take all the terms that include $x$ to the left and all other terms to the right: $10x-4x=8+5$ Simplify and solve for $x$: $6x=13$ $x=\dfrac{13}{6}$