Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 26



Work Step by Step

$\dfrac{2x-1}{x+2}=\dfrac{4}{5}$ We can apply cross-multiplication to solve this equation. $5(2x-1)=4(x+2)$ Evaluate the products: $10x-5=4x+8$ Take all the terms that include $x$ to the left and all other terms to the right: $10x-4x=8+5$ Simplify and solve for $x$: $6x=13$ $x=\dfrac{13}{6}$
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