Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.5 - Equations - 1.5 Exercises - Page 56: 20


$\frac{2}{5}x-1=\frac{3}{10}x+3$ Solution: $x=40$

Work Step by Step

1. $\frac{2}{5}x-1=\frac{3}{10}x+3$ 2. Add 1 to each side: $\frac{2}{5}x=\frac{3}{10}x+4$ 3. Divide each side by $\frac{2}{5}$ (equivalent to multiplying each side by $\frac{5}{2}$):$x=\frac{15}{20}x+\frac{20}{2}$ 4. Reduce fractions: $x=\frac{3}{4}x+10$ 5. Subtract $\frac{3}{4}x$ from each side: $\frac{1}{4}x=10$ 6. Divide each side by $\frac{1}{4}$ (equivalent to multiply each side by 4): $x=40$
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