## Precalculus: Mathematics for Calculus, 7th Edition

$\frac{2}{5}x-1=\frac{3}{10}x+3$ Solution: $x=40$
1. $\frac{2}{5}x-1=\frac{3}{10}x+3$ 2. Add 1 to each side: $\frac{2}{5}x=\frac{3}{10}x+4$ 3. Divide each side by $\frac{2}{5}$ (equivalent to multiplying each side by $\frac{5}{2}$):$x=\frac{15}{20}x+\frac{20}{2}$ 4. Reduce fractions: $x=\frac{3}{4}x+10$ 5. Subtract $\frac{3}{4}x$ from each side: $\frac{1}{4}x=10$ 6. Divide each side by $\frac{1}{4}$ (equivalent to multiply each side by 4): $x=40$