Answer
The point $B$ is closer to the point $C$
Work Step by Step
$A(4,4);$ $B(5,3);$ $C(-1,-3)$
To find the distance between to points, use the following formula:
$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$
Find the distance between $A$ and $C$. For these two points, $x_{1}=4$, $y_{1}=4$, $x_{2}=-1$ and $y_{2}=-3$
$d_{AC}=\sqrt{(-1-4)^{2}+(-3-4)^{2}}=\sqrt{(-5)^{2}+(-7)^{2}}=...$
$...=\sqrt{25+49}=\sqrt{74}\approx8.6023$
Find the distance between $B$ and $C$. For these two points, $x_{1}=5$, $y_{1}=3$, $x_{2}=-1$ and $y_{2}=-3$
$d_{BC}=\sqrt{(-1-5)^{2}+(-3-3)^{2}}=\sqrt{(-6)^{2}+(-6)^{2}}=...$
$...=\sqrt{36+36}=\sqrt{72}=6\sqrt{2}\approx8.4853$
Since $d_{BC}\lt d_{AC}$, the point $B$ is closer to the point $C$
