Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 135: 90

Answer

$$-1\leq x \leq 1$$ Also see the image below. Blue part corresponds to the interval.

Work Step by Step

Following the solving steps of inequality, we write: $x^2-1\leq0$ Let the expression on the left side of inequality equal to $y$ $y=x^2-1$ and graph it. See the red graph on the image above. We need the part of the graph that lies below and including $x$-axis as we are asked for ($\leq$) in the beginning. So our solution is $[-1, 1]$ Using interval notation: $-1\leq x \leq 1$
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