Answer
$(x-2)^{2}+(y+5)^{2}=2$
Work Step by Step
$C(2,-5);$ $r=\sqrt{2}$
The equation of a circle with center $(h,k)$ and radius $r$ is:
$(x-h)^{2}+(y-k)^{2}=r^{2}$
The center and the radius are given. Substitute them into the formula and simplify to obtain the equation of the circle:
$(x-2)^{2}+(y+5)^{2}=(\sqrt{2})^{2}$
$(x-2)^{2}+(y+5)^{2}=2$
