Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 655: 40

Answer

$21i-2j-5k$

Work Step by Step

Let us consider two vectors $v=pi+qj+rz$ and $w=xi+yj+zk$; then we have: $v+w=(p+x)i+(q+y)j+(r+z)k$ The magnitude of any vector (let us say $v$) can be determined using the formula $||v||=\sqrt{p^2+q^2+r^2} $ Therefore, $4v-3w=4 (3i+j+2k)-3(-3i+2j-k) \\ =12i+4j-8k+9i-6j+3k\\ =21i-2j-5k$
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