Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 655: 20

Answer

$z\cdot w=6(cos0+i\ sin0)=6$, $\frac{z}{w}=\frac{3}{2}(cos(\frac{8\pi}{5})+i\ sin(\frac{8\pi}{5}))$

Work Step by Step

1. Use the given numbers, we have $z\cdot w=6(cos(\frac{9\pi}{5}+\frac{\pi}{5})+i\ sin(\frac{9\pi}{5}+\frac{\pi}{5}))=6(cos(2\pi)+i\ sin(2\pi))=6(cos0+i\ sin0)=6$ 2. we have $\frac{z}{w}=\frac{3}{2}(cos(\frac{9\pi}{5}-\frac{\pi}{5})+i\ sin(\frac{9\pi}{5}-\frac{\pi}{5}))=\frac{3}{2}(cos(\frac{8\pi}{5})+i\ sin(\frac{8\pi}{5}))$
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