Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 655: 35

Answer

$\dfrac{-2 \sqrt 5}{5}i+\dfrac{\sqrt 5}{5}j$

Work Step by Step

Let us consider two vectors $v=pi+qj$ and $w=xi+yj$; then we have the unit vector $u$ in the same direction as $v$ as: $u=\dfrac{v}{||v||}$ and the magnitude of any vector (let us say $v$) can be determined using the formula $||v||=\sqrt{p^2+q^2} $ We have: $||v||=\sqrt {(-2)^2+(1)^2}=\sqrt {5}$ Therefore, the unit vector $u$ in the same direction as $v$ is: $u=\dfrac{v}{||v||}=\dfrac{ -2i+j}{\sqrt 5}=\dfrac{-2 \sqrt 5}{5}i+\dfrac{\sqrt 5}{5}j$
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